lz磁悬不解释 |
:jd{:3_67:}不威胁就没让你理,晕死算了 我们老师讲的是把那个S下面的n+1使劲换,一直换到n+3 LS的答案还在审核中,看你的最后一步,好像得不出来什么:jd |
(5n-8)S[n+1]-(5n-8)S[n]-10S[n]=an+b (5n-8)a[n+1]-10S[n]=an+b (5n-13)a[n]-10S[n-1]=an-a+b (5n-8)a[n+1]-(5n-13)a[n]-10a[n]=a (5n-8)a[n+1]-(5n-3)a[n]=a a[n+1]/[5(n+1)-8]-a[n]/(5n-8)=a/[(5n-3)(5n-8)]=(a/5)[1/(5n-3)-1/(5n-8)] 求和可得 a[n+1]/(5n-3)-a[1]/(-3)=(a/5)[1/(5n-3)-1/(-3)] a[n+1]=(a/5+1)(5n-3)+a/5 |
{:3_65:}:am要是再没人理,打死我也不发题了 |
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