求解这个方程组嗯。

格物知理

就是算到了这一步cx+ay+bz=0，bx+cy+az=0之后怎么出现这个 呢？求解，谢谢。

杨梦如

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\[\begin{array}{l}
1 - 4.a,b,c > 0,:\\
(1 + \frac{a}{b})(1 + \frac{b}{c})(1 + \frac{c}{a}) \ge 2(1 + \frac{{a + b + c}}{{\sqrt[3]{{abc}}}}).\\
\frac{{(1 + \frac{a}{b})(1 + \frac{b}{c})(1 + \frac{c}{a}) - 2}}{2} = \frac{a}{b} + \frac{b}{c} + \frac{c}{a} \ge \frac{{a + b + c}}{{\sqrt[3]{{abc}}}}
\end{array}\]

格物知理

杨梦如 发表于 2012-8-14 11:41
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这是。。？{:F36:}

格物知理

木有人吗。。。

kuafuzhuiri

真复杂。。

格物知理

kuafuzhuiri 发表于 2012-8-22 20:48
真复杂。。

是很复杂{:F16:}

格物知理

。。。。。。